General Palindromic Number
题目链接:1019 General Palindromic Number (20 point(s))
题干大意
D进制问题+判断回文数
思路
很常规,只是两个问题结合在一起而已
AC代码
C++ |
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| #include <iostream>
#include <vector>
using namespace std;
int main()
{
int n, b;
cin >> n >> b;
vector<int> ans;
do {
ans.push_back(n % b);
n /= b;
} while (n != 0);
bool flag = true;
for (auto i = 0; i != ans.size() / 2; ++i) {
if (ans[i] != ans[ans.size() - i - 1]) {
flag = false;
break;
}
}
flag ? (cout << "Yes\n") : (cout << "No\n");
for (auto i = ans.size() - 1; i != -1; --i) {
cout << ans[i];
if (i)
cout << " ";
}
return 0;
}
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